1/5y^2-2=-3/10y

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Solution for 1/5y^2-2=-3/10y equation: 


y in (-oo:+oo)

(1/5)*y^2-2 = (-3/10)*y // - (-3/10)*y

(1/5)*y^2-((-3/10)*y)-2 = 0

(1/5)*y^2+(3/10)*y-2 = 0

1/5*y^2+3/10*y-2 = 0

DELTA = (3/10)^2-(-2*1/5*4)

DELTA = 169/100

DELTA > 0

y = ((169/100)^(1/2)-3/10)/(1/5*2) or y = (-(169/100)^(1/2)-3/10)/(1/5*2)

y = 5/2 or y = -4

y in { -4, 5/2 }

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